Gradebook - is there an easy way to get a grade average (or percentage) for an entire section?
Message was edited by: Chris Hofer
I'm not sure of a way to do this within the Gradebook, but you could download the scores (How do I download grades from the Gradebook? ) and filter the downloaded CSV file to only display the section you want to look at, if there are multiple sections. You could then calculate the average for the section, as shown below.
That's the easiest way I can think of doing it. Hopefully it helps!
While I don't really have an answer for you, I wanted to let you know that I am going to modify the subject line of your question because it is the same as in the body of your message. I am also going to tag your message with keywords. Both of these things will make it easier for people to search for your topic should they have similar questions. If the revised subject line doesn't accurately reflect what you are asking in the body of your message, please let me know, and we can make any necessary changes. I hope this is okay with you.
I would very much like to see this feature. Just a simple overall average for each section can give a helpful snapshot of how courses are progressing in relation to one another, and can help identify if there are particular areas of need. (And really, teachers shouldn't have to download, filter, and average all of their scores just to get such an easily-added feature.)
Matthew, you might want to suggest a The specified item was not found. idea to gauge Community support for such a feature. Please refer to How do I create a new feature idea? and How to write a good feature idea submission
I saw it! To close the loop, and for any interested parties, here's the link to the feature idea: Include a Section Overall Average in Gradebook
(edited to correct the link to the feature idea)
That link seems to redirect back to this discussion, here's the link to the feature idea - Include a Section Overall Average in Gradebook
Whoops, good catch, Kona--thanks! Sometimes my mouse has a memory of its own. I've edited my reply so that people don't get caught in an endless loop.
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